Question

A number selected at random from first 50 natural numbers. find the probabiltiy that it is a multiple of 3 and 4​

Answer 1

Step-by-step explanation:

n(s)=1,2,3,....,50

multiple of 3=3,6,9,....,48

number of multiples of 3=16

number of multiples of 4=12

number of multiples of 3 and 4=4

∴n(A)=16+12−4=28−4=24

P(E)=5024=2512

Answer 2

Answer:

So if “first 50 natural numbers” means the numbers ranging from 1 to 50, then we can see that 4 of those numbers are multiples of 12. So 4/50 = 2/25 = 8% is the probability of a uniformly chosen random number in that range being a multiple of both 3 and 4.

Step-by-step explanation:

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