Question

A number was divided successively in order by 4 5 and 6 and remainders were 2,3 and 4 what is the number

Answer 1

that no. is 58.....

bcoz divide 58 by 4 we get ...

2 as reminder....

divide it by 5 we get reminder

as 3

divide it by 6 we get

4 as reminder.....

plz mark as brainliest.....☺❤

Answer 2

Let  p  be the number

p/4 =q,  remainder 2

q/5  =r,  remainder 3

r/6 = s,  remainder 4

r = 6s + 4

q = 5r + 3 = 5(6s + 4) + 3  =  30s + 23

p = 4q + 2 = 4{30s+ 23} + 2

p = 120s + 94

Suppose s = 1,    

p = 120*1 + 94 =   214