Question

A number when devided by 3 leaves a remainder 1. When the quotient is devided by 2, it leaves a remainder 1. What will be the remainder when the number is devided by 6 ?

Answer 1

Answer:

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Step-by-step explanation:

$let \: number \: be \: x. \\ x = 3q + 1......... |1| \\ q = 2p + 1......... |2| \: \\ eq \: is \: possible \: only \: if \: q \: is \: odd. \\ so \: put \: q = 1..3..5.. 2 _ {n - 2} \\ it \: q = 3 \\ x = 10 \\ it \: 6 \: divides \: 10.. it \: will \: leave \: reminder \: as \: 4 \\ if \: q = 5 \\ x = 16 \\ again \: remainder \: will \: be \: 4$

Answer 2

Answer:

letnumberbex.

x=3q+1.........∣1∣

q=2p+1.........∣2∣

eqispossibleonlyifqisodd.

soputq=1..3..5..2

n−2

itq=3

x=10

it6divides10..itwillleavereminderas4

ifq=5

x=16

againremainderwillbe4