A number when divided by 169 leaves 91 as remainder.What about be the remainder when the same number is divided by 13 ? Please give answer step wise with sufficient explanations.
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Dividend = Divisor × Quotient + Remainder
Let the Dividend be "a" and Quotient be "b"
a = 169×b+91
a= 169b +91
So , 169b +91 denote a
Taking out 13 as common
a=13(13b+7)
Here , if we see it in form of the divisor rule
13 is divisor ,( 13b+7) as quotient and 0 as remainder.
Let the Dividend be "a" and Quotient be "b"
a = 169×b+91
a= 169b +91
So , 169b +91 denote a
Taking out 13 as common
a=13(13b+7)
Here , if we see it in form of the divisor rule
13 is divisor ,( 13b+7) as quotient and 0 as remainder.
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