Question

A number when divided by 5 multiplied by 7, divided by 14 again and then multiplied by 10 remains unchanged. find the number

Answer 1

let the no. is x

{(x/5)×7/14}×10=x

{(x/5)×1/2}×10=x

{x/10}×10=x

x=x

we can say no. is ..... -2,-1, 1,2,3,4.........

Answer 2

Given,

A number, when divided by 5, multiplied by 7, divided by 14 again, and then multiplied by 10, remains unchanged.

To find,

Find the number.

Solution,

• Let us assume the number, A= X.

• After division by 5, the number A will be ⇒ X/5.

• According to the question, the number A is then multiplied by 7. Hence the number would become A ⇒ 7X/5.

• In the next step, the number A is again divided by 14. Therefore further solving,

         ⇒  A = (7X/5)÷14

         ⇒  A = X/10.

• The number A is multiplied by 10. So, we would get.

         ⇒ A = (X/10)×10= X.

The number A after all the mathematical operations is X only that we assumed earlier.

Hence, the number can be any REAL number, because after all the mathematical operations we would get the same number that we assumed earlier.