Math, asked by dilpreetkaur1146, 1 year ago

A number when divided by 627 leaves a remainder 43.By dividingtha same numberby19,the remainder well be

Answers

Answered by Anonymous
0

Answer:

n leaves remainder 5 when divided by 19

Step-by-step explanation:

Notice that 627 = 19×33.  So...

n leaves remainder 43 when divided by 627

=> n = 627k + 43    for some integer k

=> n = 19(33k) + 43 = 19(33k) + 38 + 5  = 19(33k+2) + 5

=> n leaves remainder 5 when divided by 19

Answered by Ayeshasheik
0

Answer: 5

Step-by-step explanation:

On dividing a number by 627, Let k b the quotient and 43 as remainder.

The number=627k+43=(19*33k)+{(19*2)+5}

=19(33k+2)+5

So a number when divided by 19 , (33k+2) is quotient and 5 is the remainder

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