A number when divided by 627 leaves a remainder 43.By dividingtha same numberby19,the remainder well be
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Answered by
0
Answer:
n leaves remainder 5 when divided by 19
Step-by-step explanation:
Notice that 627 = 19×33. So...
n leaves remainder 43 when divided by 627
=> n = 627k + 43 for some integer k
=> n = 19(33k) + 43 = 19(33k) + 38 + 5 = 19(33k+2) + 5
=> n leaves remainder 5 when divided by 19
Answered by
0
Answer: 5
Step-by-step explanation:
On dividing a number by 627, Let k b the quotient and 43 as remainder.
The number=627k+43=(19*33k)+{(19*2)+5}
=19(33k+2)+5
So a number when divided by 19 , (33k+2) is quotient and 5 is the remainder
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