Question

A number when successively divided by 5, 3, 2 gives remainder 0, 2, 1 respectively in that order. What will be the remainder when the same number is divided successively by 2, 3, 5 in that order?​

Answer 1

2x+1

3*(2x+1)+2

5*[3*(2x+1)+2]

=30x+25

{30x+25}/2=15x+12(rem=1); [15x+12]/3=5x+4 (rem=0); (5x+4)/5=x (rem=4)

ans is 1,0,4

Answer 2

2x+1

3*(2x+1)+2

5*[3*(2x+1)+2]

=30x+25

{30x+25}/2=15x+12(rem=1); [15x+12]/3=5x+4 (rem=0); (5x+4)/5=x (rem=4)

ans is 1,0,4