a number which when divided by 143 leaves 31 as a remainder . what will be the remainder when the same number is divided by 13?
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when we divided the same number by 13 we got a remainder 11
akansha91:
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We know that,
Dividend = Divisor × Quotient + Remainder (by Euclid's division lemma)
It is given that:
Divisor = 143
Remainder = 13
So, the given number is in the form of 143x + 31, where x is the quotient.
∴ 143x + 31 = 13 (11x) + (13 × 2) + 5
= 13 (11x + 2) + 5
Thus, the remainder will be 5 when the same number is divided by 13.
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