Question

A number which when divided by 779, gives a remainder of 47.by dividing the same number by 19, what would be the remainder

Answer 1

Only divide 47 by 19. We get the answer.

47 divided by 19 leaves remainder 9. So 9 is the answer.

If a number divided by 779 leaves remainder 47, 47 also will have been the value for the number.

As the number leaves remainder 47 on division by 779, let the number be 779x + 47.

If x = 0, 779x + 47 = 779 × 0 + 47 = 0 + 47 = 47

So that's why the remainder got by dividing 47 by 19 would have been the answer.

9 is the answer.

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Answer 2

Answer: Remainder is 9

Step-by-step explanation: A number which when divided by 779, gives a remainder of 47.

Assume the number is $x$ ( Dividend)

Formula - Dividend = Divisor × Quotient + Remainder

Given that - Dividend = $x$

                    Divisor = 799

                     Remainder = 47

                     Quotient = Q

putting the values - $x$ = 799 × Q + 47

                                 $x$ = 799Q + 47

                                 $x$ = ( 19 × 41 )Q + (19×2) + 9 ← ∵ ( 47 = 19 × 2 + 9)

                                             ↑            

                                      Factorization of 799

                 (Number) $x$ = 19 ( 41Q + 9) + 9  ( taking 19 common)

∵ Dividing the same number by 19

       So       Number = 19 × new quotient + R    ….(1)

Comparing both the equation

                   New quotient = 41Q + 9

                      Remainder = 9