Math, asked by chintu1305, 1 year ago

a number whose seventh part exceeds its eighth part by 2

Answers

Answered by SparshSharmaofAPScl9
23

Answer:


Step-by-step explanation:

(1/7)x=(1/8)x+2

x/7=(x+16)/8

8(x/7)=x+16

8x=7(x+16)

8x=7x+128

8x-7x=128

x=128

Answered by wifilethbridge
9

The number is 112

Step-by-step explanation:

Let the number be x

One seventh of number = \frac{x}{7}

One eight of number = \frac{x}{8}

We are given that  seventh part exceeds its eighth part by 2

\frac{x}{7}-\frac{x}{8}=2\\\frac{8x-7x}{56}=2\\x=56 \times 2

x = 112

Hence The number is 112

#Learn more:

The sum of a number and twice the number is 57.

https://brainly.in/question/12488158

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