Question

A number x is equal to its own square minus 42 . find two possible values of x .
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Answer 1

According to question:-

x = x² - 42

Now,solve this quadratic equations.....

x^2 - x - 42 = 0

x^2 - 7x + 6x - 42 = 0

x(x - 7) + 6(x - 7) = 0

(x + 6)(x - 7) = 0

x + 6 = 0 or x - 7 = 0

x = -6 or x = 7