Question

A number x is selected at random from the number 1, 4, 9, 16 and another number
y is selected at random from the number 1, 2, 3, 4. Find the probability that the
value of xy is more than 16.
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Answer 1

Answer:

xy > 16

9×2= 18

9×2,9×3,16×2,16×3,16×4

favourable cases are 6

total cases are 16

required probability = 6/16