Question

A number x is selected at random from the numbers 1,2,3 and 4. Another number y is
selected at random from the numbers 1, 4, 9 and 16. Find the probability that product of x and
y is less than 16.​

Answer 1

Answer:

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Asked on December 20, 2019 byRion Kathir

A number x is selected at random from the numbers 1,2,3 and 4. Another number y is selected at random from numbers 1,4,9 and 16. Find the probability that product of x and y is less than 16.

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ANSWER

xy<16

If x=1

y can be =1,4,9

⇒Probability=41×43=163

If x=2

y can be =1,4

Probability=41×42=81

If x=3

y can be =1,4

Probability=41×42=81

If x=4

y=1

Probability=41×41=161

∴ Probability of selecting x,y such that

xy<16

is =3/16 + 1 by 8 +1 by 8 +1 by 16

3 by 16+1 by 16 + 2 by 8

1 by 4+ 1 by 4

=1 by 2

HOPE IT IS HELPFUL TO YOU

Answer 2

Answer:

1/2

Step-by-step explanation:

Given, x={1,2,3,4}

n(x)=4

y={1,4,9,16}

n(y)=4

Total no. of possible products

=4×4=16

Products x.y which are less than 16 are {1×1,1×4,1×9,2×1,2×4,3×1,3×4,4×1}

n(x.y)=8

Required probability =8/16 =1/2

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