Question

A student measures the mass of an object five times. The data are 2.46 kg, 2.47 kg, 2.41 kg, 2.42 kg and 2.44 kg. The reported mean mass with error should be:
2.44 +0.01 kg
2.44 +0.02 kg
2.44 + 0.03 kg
2.44 + 0.04 kg​

Answer 1

Answer:

2.44 + 0.02 kg is correct

Answer 2

The reported mean mass with error should be 2.44 + 0.02

Option (2) is correct

Explanation:

The data are 2.46 kg, 2.47 kg, 2.41 kg, 2.42 kg and 2.44 kg

Mean: It is average value of all data (sum of data divide by number of data)

$\text{Mean}=\dfrac{2.46+2.47+2.41+2.42+2.44}{5}$

$\text{Mean}=2.44$

Mean = 2.44

Mean error: It is sum of absolute value of difference with mean divide by number of data.

$MEN=\sum\dfrac{|x_i-\bar{x}|}{5}$

$\text{mean Error}=\dfrac{\left|2.44-2.46\right|+\left|2.44-2.47\right|+\left|2.44-2.41\right|+\left|2.44-2.42\right|+\left|2.44-2.44\right|}{5}$

Error = 0.02

The reported mean mass with error should be 2.44 + 0.02

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