A number x is selected from (1, 2, 3) and another number y is selected from (1,4,9). The probability
that the product is less than 9 is:
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A number x is selected from the numbers 1, 2, 3 and then a second number y is randomly selected from the numbers 1, 4, 9. What is the probability that the product xy of the two numbers will be less than 9 ?
Number x can be selected in three ways and corresponding to each such way there are three ways of selecting number y. Therefore, two numbers can be selected in 9 ways as listed :
(1,1),(1,4),(1,9),(2,1),(2,4),(2,9),(3,1),(3,4),(3,9)
So, total number of elementary events = 9
The product xy will be less than 9, if x, and y are chosen in one of the following ways :
(1,1),(1,4),(2,1),(2,4),(3,1)
Therefore, favourable number of elementary events = 5
Therefore, required probability = 9 /5
Step-by-step explanation:
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