a number x twiced is equally to 19times another number y. when y is subtracted form 44 another number z is formed. find the value of x,y, and z
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according to the question
2x=19y
or x/y=19/2
if we assume x=19
y=2
&
also
44-y=z
then z=42
x=19
y=2
z=42
2x=19y
or x/y=19/2
if we assume x=19
y=2
&
also
44-y=z
then z=42
x=19
y=2
z=42
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