Math, asked by yrenu319, 11 months ago

A numeric lock has a 3 digit key GIVE A Question solve

HINT
682
614
204
738
780

Answers

Answered by poojan
0

Therefore, the co-de of the given numerical lock is 042.

Decoding the clues given:

On observing the rules given, from the fourth rule, we get that the lock contains no numbers from the list [7, 3, 8]. So, from the first rule 6, 2 remains.

From the second rule, we get that one number among 6, 1, 4 is correct but wrongly placed. But the number 6 is in the same position in rules 1 and 2. So, there is no chance of 6 being among the three numbers of the lock.

So, from the first rule, we get that the number at the last position is 2 as it says that the number is well placed.

_ _ 2

In the third rule, if we eliminate 6, the remaining numbers are 2, 0. They are correct but wrongly placed. As 2 is fixed with the last position, 0 goes for the first position as per the rule.

0 _ 2

Now, from rule 2, we get that one number is correct among 1, 4 but is wrongly placed. If 1 is correct, it would be well placed and that contradicts the rule which says that the number is wrongly placed. So, the correct number that should be in the second position is 4

0 4 2

Therefore, the co-de of the given numerical lock is 042.

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