Question

A numerical a car of mss 1000kg is moving with velocity 54 km/h stop in 5 sceonds claculate force

Answer 1

Correct Question-

A a car of mass 1000kg is moving with velocity 54 km/h stop in 5 seconds. Calculate force applied .

Answer-

Given -

-> mass,m = 1000 kg

-> initial velocity,v = 54 m/s = 15 m/s

-> t = 5s

-> final velocity,u = 0 m/s

solve -

By first equation of motion-

v-u = at

a = v-u/t

a = 15-0/5

a = 3 m/s^2

Force = mass × acceleration

Force = 1000 × 3 m/s^2

Force applied = 3000 N

Answer 2

Answer:

$\bold\red{GIVEN:}$

Initial Velocity (u) = 54 km/hr

Time Taken (t) = 5 second

Mass of the car = 1000 kg

Final velocity (v) = 0 m/s [Car stopped]

$\bold\pink {TO \ FIND:}$

The magnitude of force applied on the body

$\bold\purple {SOLUTION:}$

Let the acceleration of the car be 'a' m/s²

Initial Velocity = 54 km/hr

Change the initial Velocity in m/s:-

u = 54 km/hr

u =$\sf{ 54 \times \dfrac{5}{18}}$

u = 15 m/s

To find the acceleration of the car, we use the formula:-

$\large{\boxed{\bf{ a = \dfrac{v-u}{t} }}}$

According to question:-

$\sf{\longrightarrow a = \dfrac{0-15}{5} }$

$\sf{\longrightarrow a = \cancel\dfrac{-15}{5}}$

$\bf{\longrightarrow a = -3 \: m/s^2 }$

* The acceleration of the car is –3 m/s² *

We know the formula for finding the force is:-

$\large{\bf{ \: FORCE = m \times a }}$

On putting the given values in the formula, we get

$\sf{\longrightarrow F = 1000 \times -3 }$

$\sf{\longrightarrow F = -3000 \: N}$

$\bf{\longrightarrow F = 3000 \: N}$

Hence, the magnitude of force applied on the car is 3000 N