Solve: 1/3x+y +1/3x-y=3/4,1/2(3x+y)+21/2(3x-y)=9
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Answered by
0
Answer:
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Step-by-step explanation:
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Answered by
1
Answer:
3x+y
1
+
3x−y
1
=
4
3
4(3x+y+3x−y)=3((3x+y)(3x−y))
4(3x+3x)=3(9x
2
−y
2
)
24x=27x
2
−3y
2
−y
2
+9x
2
−8x=0...(1)
2(3x+y)
1
−
2(3x−y)
1
=−
8
1
(3x+y)
1
−
(3x−y)
1
=−
4
1
4(3x+y−3x−y)=−1((3x+y)(3x−y))
4(−2y)=−1(9x
2
−y
2
)
−8y=−9x
2
+y
2
y
2
−9x
2
+8y=0...(2)
From (1) and (2), we get
x=y
Substituting the value of x in eqn (2), we get
y
2
−9x
2
+8y=0
y
2
−9y
2
+8y=0
−8y
2
+8y=0
8y
2
=8y
⇒y=1
⇒x=y=1
hope it will help you
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