Math, asked by gurpreetkaur7692, 10 months ago

Solve: 1/3x+y +1/3x-y=3/4,1/2(3x+y)+21/2(3x-y)=9

Answers

Answered by sarthakgholap7
0

Answer:

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Step-by-step explanation:

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Answered by hanshapahadi0182
1

Answer:

3x+y

1

+

3x−y

1

=

4

3

4(3x+y+3x−y)=3((3x+y)(3x−y))

4(3x+3x)=3(9x

2

−y

2

)

24x=27x

2

−3y

2

−y

2

+9x

2

−8x=0...(1)

2(3x+y)

1

2(3x−y)

1

=−

8

1

(3x+y)

1

(3x−y)

1

=−

4

1

4(3x+y−3x−y)=−1((3x+y)(3x−y))

4(−2y)=−1(9x

2

−y

2

)

−8y=−9x

2

+y

2

y

2

−9x

2

+8y=0...(2)

From (1) and (2), we get

x=y

Substituting the value of x in eqn (2), we get

y

2

−9x

2

+8y=0

y

2

−9y

2

+8y=0

−8y

2

+8y=0

8y

2

=8y

⇒y=1

⇒x=y=1

hope it will help you

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