Math, asked by tashviattri, 4 months ago

A nursery school playground is 160 m long and 80 m wide. In it 80 m × 80 m is kept for swings and in the remaining portion, there are 1.5 m wide paths parallel to its width and parallel to its remaining length as shown in Figure. The remaining area is covered by grass. Find the area covered by grass.

Answers

Answered by jainakshat87871
22

Step-by-step explanation:

area of playground=length ×breadth =160×80=12800squaremetre

area covered by swings=side×side=80×80=6400squaremetre

area of paths=area of 2rectangles -area of square

= 2 (L×B)-side×side

=2 (1.5×80)-1.5×1.5

=240-2.25

=237.75squaremetre

area covered by grass=area of playground-(area covered by swings+area of paths)

=12800-(6400+237.75)

=12800-6162.25

=6637.75squaremetre

6637.75squaremetre is the correct answer

I HOPE IT IS VERY HELPFUL........

Answered by Anonymous
10

Area of the playground = l × b = 160 m × 80 m = 12800 m²

Area left for swings = l × b = 80m × 80m = 6400 m²

Area of the remaining portion = 12800 m² – 6400 m² = 6400 m²

Area of the vertical road = 80 m × 1.5 m = 120 m²

Area of the horizontal road = 80 m × 1.5 m = 120 m²

Area of the common portion = 1.5 × 1.5 = 2.25 m²

Area of the two roads = 120 m² + 120 m² – 2.25 m²= (240 – 2.25) m² = 237.75 m²

Area of the portion to be planted by grass = 6400 m² – 237.75 m² = 6162.25 m²

Hence, the required area = 6162.25 m²..

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