Question

A object is placed at a distance of 30cm from
convex mirror ,the magnification produced is 1/2
where should the object be placed to get a
magnituistan of 1/3 ?​

Answer 1

Answer:

ATQ 1st condition

Object dist.=-30cm

image dist.=v

magnification=1/2

magnification=v/u

=>1/2=v/-30

v=-30/2=-15cm

ATQ 2nd condition

object dist.=u

image dist.=15cm

magnification=1/3

magnification=v/u

m=1/3=15/u

therefore,u=5cm <=Ans.