A object is vertically upward with a velocity of 20m/s
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Answer:
Given that
A object is thrown vertically upward direction
let us take the y-axis inthe vertically upward direction with zero at the ground
Now,
V0 = +20m/s
a = -g = 10m/s
V = 0m/s
"If the object rise to height 'y' from the point of launch"
V2 = (V0)2 + 2a ( y - y0 )
We get ,
0 = (20)2 + 2(-10) (y-y0)
So , (y-y0) = 20m
The total time taken
h = -ut + 1/2gt2
Now , put
h = 25m
u = 29m/s
g = 10m/s
25 = -20t + ( 1/2 ) 10t2
5t2 - 20t - 25 = 0
t2 - 4t - 5 = 0
t2 - 5t + t - 5 = 0
t [ t-5 ] + 1[ t-5 ] = 0
t = 5s
Therefore total time taken (t) = 5 sec.
Explanation:
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