Question

a object of size 7 cm is placed at 27 CM in front of a concave mirror of a focal length 10 cm at what distance from the mirror should be screen is is placed so that a shop poker image can be obtained then find the size and nature of the image ?
Please koi please thanks dedo re . ​

Answer 1

Explanation:

We get the image size to be double the object size with a negative sign. This means that the image formed will be real and inverted in nature. The image formed by the object in front of a concave mirror is 14 cm in size, is 54 cm in front of the mirror and is real and inverted in nature. This is the required solution.

Answer 2

ǫᴜᴇsᴛɪᴏɴ →

a object of size 7 cm is placed at 27 CM in front of a concave mirror of a focal length 18 cm at what distance from the mirror should be screen is is placed so that a shop poker image can be obtained then find the size and nature of the image ?

ᴀɴsᴡᴇʀ →

Mirror formula :

$\longmapsto\tt{\dfrac{1}{v} + \dfrac{1}{u} = \dfrac{1}{f} = ....(1)}$

So,

$\longmapsto\tt{ u = −27cm}$

Concave mirror have negative focal length.

$\longmapsto\tt{f = − \: 18cm}$

Putting the values in (1),

$\longmapsto\tt{\dfrac{1}{v} + \dfrac{1}{ - 27} = \dfrac {1}{ - 18} }$

We get, v = − 54cm

Also,

$\longmapsto\tt{Magnification=\dfrac{h²}{h¹}</u><u>\dfrac{-v}{u}}$

$\longmapsto\tt{\dfrac{h²}{7.0}= - \dfrac{-54}{-27}}$

$\longmapsto\tt{h²=−14.0cm}$

Image will be real and inverted and will be of size 14 cm.

vo 10 cm nhi 18 cm hai