Question

A object starting from rest acquires a velocity of 25m/s in 10s .If mass of object is 3kg .Find Force applied on the object.


Hint:-


Find Acceleration then Use newtons second law .




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Answer 1

Answer :-

A force of 7.5 Newtons was applied on the object .

Explanation :-

We have :-

→ Initial velocity (u) = 0 m/s

→ Final velocity (v) = 25 m/s

→ Mass of the object (m) = 3 kg

→ Time taken = 10 sec

To find :-

→ Force (F)

______________________________

Firstly, let's calculate acceleration of the object by using the 1st equation of motion .

v = u + at

⇒ 25 = 0 + a(10)

⇒ 25 - 0 = 10a

⇒ 25 = 10a

⇒ a = 25/10

⇒ a = 2.5 m/s²

Now, we can calculate the measure of force by using Newton's 2nd law of motion .

F = ma

⇒ F = 3(2.5)

⇒ F = 7.5 N

Answer 2

Answer:-

• Initial velocity=u=0m/s
• Final velocity=v=25m/s
• Time=10s=t
• Mass=m=3kg

• Force=F=?

We know

$\boxed{\sf Acceleration(a)=\dfrac{v-u}{t}}$

According to Newton's Second law.

$\boxed{\sf F=ma}$

• Putting Formula of Acceleration

$\\ \sf\longmapsto F=\dfrac{m(v-u)}{t}$

$\\ \sf\longmapsto F=\dfrac{3(25-0)}{10}$

$\\ \sf\longmapsto F=\dfrac{3(25)}{10}$

$\\ \sf\longmapsto F=\dfrac{75}{10}$

$\\ \sf\longmapsto F=7.5N$

Hence a force of 7.5N was applied on the object.