A of mass 10 kg starts from rest and rolls down an inclined plain. it rolls down 10 metrein 2 seconds? t=4.47sec
( a)what is the acceleration attained the body ?
( b) what is the velocity of the body at 2s?
( c) what is the force on the body
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Answer:
Force acting on the body is 50N
Explanation:
(a) Distance travelled= 10m. , Time= 2s
Using the formula,
S= ut+ 1/2 at. square
10=0×2+1/2×a×2. square
10= 2a
a= 10/2 = 5m/s. square
(b) Acceleration=5m/s. square
time= 2s
v= u+at
v=0+2×5. , v= 10m/s
(c) mass= 10kg
Acceleration= 5m/s. square
F= ma
= 10×5
= 50N
So, Force acting on the body is 50N
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