Question

A one dimensional array A has indices 0...54.each element is a string and takes up four memory words.tbe array is stored starting at location 1000 in decimal form.the starting address of 41th element of A is​

Answer 1

Answer:

1164

Explanation:

Address of array + index *size of element  when index starts from 0

In above question index starts from 0

so given Address of array=1000 , index=41 , size of element=4

Address=1000+(41-0)*4 = 1000 + 164=1164