Question

A one litre flask of glass has some mercury. it is seen that at different temperature the volume of air inside the flask remains the same. find the volume of mercury in the flask. α(alpha) for glass is 9×10^-60 c and y for mercury is 1.8*10^-40 c^-1 ?

Answer 1

here is your answer mate!!

Solution: If V is the volume of flask, VL of mercury and VA of air in it,

V = VL + VA

Now as with change in temperature volume of air remains constant, the expansion of mercury will be equal to that of the whole flask i.e.,

ΔV = ΔVL

VγG Δθ = VLγL Δθ

[ As , ΔV = Vγ Δθ ]

Here V = 1 litre = 1000 cc and γG = 3 α G = 27 x 10-6 / °C

VL = (1000 x 27 x10-6 /1.8 x 10-4 / )= 150 cc.