Question

some one please.....​

Answer 1

let, mass of each bullets is m

so, mass of n bullets which is fire is nm

for Newton second law of motion

F = nma

=> F =nm dv/dt (°•° a = dv/dt)

=> Fdt = nmdv

=> 144×1 = n×(40/1000)×(1200)

=> 144 = 48n

=> n = 3

hence , number of bullets fire per second is 3