Question

A one litre vessel initially contain s 2.0,0.5 and 0.0 moles of N2,H2 AND NH3 RESPECTIVELY. The system after attaining equilibrium has 2.0 mole of nh3. The number of moles of n2 in the vessel at equilibrium is

Answer 1

N2+3H2----------2NH3

initial mol. 2 0.5 0.0

at eq 2-x 0.5-3y 0.2

as dissociated mole gives resultant moles product so,

x+3y=0.2

total moles at eq.=2-x+0.5-3y+0.2

Nt= 2.7-x-3y

as resultant mole of nh3 after balancing the reaction of nh3=2

so,

2=2.7-x-3y

now put value of y from eq. 1

2=2.7-x-3(0.2+x/3)

2=2.7-x-0.2-x

2=2.5-2x

0.5=2x

x=0.25

at eq. N2=2-x

=2-0.25=1.85=1.9(approx.)

Thanks to u.

Answer 2

Answer:

not good

Explanation:

tooooooooooo bad