Question

A one microfarad capacitor of a TV is subjected to 4000 V
potential difference. The energy stored in capacitor is
(a) 8 J (b) 16 J
(c) 4 × 10⁻³ J (d) 2 × 10⁻³ J

Answer 1

Answer:

Energy stored in the capacitor =1/2*cv^2

Explanation:

c=1*10^-6

V=4000

Energy =1/2*10^-6*4000*4000=8 joules

Hope you are satisfied with the answer

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