A one newton pendulum bob is held at an angle theta from the vertical by a to newton horizontal force f shown as
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2.236N Ty=mg=1N Tx=2N, T=sqr((2N)^2 + (1N)^2)=sqr(5*N^2)=2.236N Without knowing the angle or length I don't know how else to solve the rest.
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in the question they clearly mentioned to find T
T = root 5
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