Question

A open pipe 85cm long is sounded. If the velocity of sound is 340 m/s.What is the fundamental freqency of vibrations of the air column?​

Answer 1

Answer:

The fundamental frequency is 200 Hz

Explanation:

Give as:

The length of open organ pipe = l = 85cm = o.85m

The velocity of sound = 340m/s.

Let the fundamental frequency = fHz

According to question

frequency = velocity of sound/ 2 length of pipe

i.e. f = 340m/ s / 2×0.85m

or, f = 340/ 1.7

:. f = 200Hz

so, the fundamental frequency = f= 200Hz.

Hence, The fundamental frequency is 200Hz Answer.

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Answer 2

Answer:

we know that the(V)=n/2l

so the length of the organ pipe = 85cm as(85×10^-2)m

the velocity of sound is 340m/s

so v=340/2×85×10^-2

V=2×10^2

V=200Hz