Math, asked by patilsheetal906, 4 months ago

a) p(x) =x2 +5x + 6

b) p(x) =x2 +11x + 24

c) p(x) =x2 +1x - 20

d) p(x) =x2 +4x - 32

e) p(x) =x2 - x + 6

Answers

Answered by NeartoBrain
1

Answer:

p(x) =x2 +5x + 6

b) p(x) =x2 +11x + 24

c) p(x) =x2 +1x - 20

d) p(x) =x2 +4x - 32

e) p(x) =x2 - x + 6

Answered by Anonymous
2

SOLUTION :-

a) p(x) = + 5x + 6

➛ x² + 5x + 6 = 0

➛ x² + 3x + 2x + 6 = 0

➛ x(x+3) + 2(x+3) = 0

➛ (x+2)(x+3) = 0

➛ x = -2 , -3

b) p(x) = + 11x + 24

➛ x² + 11x + 24 = 0

➛ x² + 8x + 3x + 24 = 0

➛ x(x+8) + 3(x+8) = 0

➛ (x+3)(x+8) = 0

➛ x = -3 , -8

c) p(x) = + x - 20

➛ x² + x - 20 = 0

➛ x² + 5x - 4x - 20 = 0

➛ x(x+5) - 4(x+5) = 0

➛ (x-4)(x+5) = 0

➛ x = 4 , -5

d) p(x) = + 4x - 32

➛ x² + 4x - 32 = 0

➛ x² +8x - 4x - 32 = 0

➛ x(x+8) - 4(x+8) = 0

➛ (x-4)(x+8) = 0

➛ x = 4 , -8

e) p(x) = - x - 6

➛ x² - x - 6 = 0

➛ x² - 3x + 2x - 6 = 0

➛ x(x-3) + 2(x-3) = 0

➛ (x+2)(x-3) = 0

➛ x = -2 , 3

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