Question

a package of aluminum foil contains 75ft2 of foil which weighs 12.00 OZ. Aluminum has a density of 2.701g/cm3. What is the thickness of foil ?

Answer 1

Explanation:

v = lwh, h = v/lw

A package of aluminum foil contains 50 ft2 of foil, which weighs approximately 9.0 oz . Aluminum has a density of 2.70 g/cm3

area = lw = 50 ft^2

So, now we have h = v/50 ft^2

9.0 oz x 28.3495g/1 oz = 255.1455 g

1 cm^3/2.70 g x 255.1455 g = 94.5 cm^3

94.5 cm^3 x (1 in/2.54cm)^3 = 5.8 in^3

5.8 in^3 x (1ft/12 in)^3 = .003337 ft^3

h = vol/50 ft^2 = .003337ft^3/50 ft^2 =

6.67 x 10^-5 ft thick.

(6.67 x 10^-5 ft) x (12 in/1 ft) x (2.54cm/1in) x (10 mm/cm) =.0203 mm

I did this the hard way. Instead, change 50 ft^2 into cm^2 to accomplish an easier set of calculations.

Answer 2

Answer:

don't know the ans

Explanation:

tried studing in 7th