Question

A packet can hold 78 pens .how many packet are required to hold 51324 pens

Answer 1

78 pens can be held in 1 packet
Hence, 51324 pens can be held in
51324/78=658 packets.

Answer is 658 packets.

Answer 2

Hi friend
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Your answer
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SOLVING (UNITARY METHOD)
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78 PENS ARE CONTAINED BY = 78 PACKETS
NO. OF PACKETS CONTAINING ONE PEN = 1/78
NO. OF PACKETS CONTAINING 51324 PENS =
$\frac{1}{78} \times 51324 \: \: packets$
= 658 PACKETS

HOPE IT HELPS

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