Question

A packett contains tickets numbered 1 to 200 . find the probability that ticket drawn has number multiple 6 or 8​

Answer 1

Answer: 0.25

Step-by-step explanation:

Multiples of 6 between 1 and 200 = 33

Multiples of 8 between 1 and 200 = 25

Common multiples of 6 and 8 are :24,48,72,96,120,144,168,192 = 8

Probability = (33+25-8)/200 = 50/200 = 0.25

Answer 2

The probability would be $\frac{1}{4}$ (or 0.25).

Step-by-step explanation:

First finding the multiples of 6 and 8 lying between 1 and 200.

• Multiples of 6 are $6, 12, 18, 24, 30, 36, 42, 48, 54, 60, 66, 72, 78,$ $84, 90, 96, 102, 108, 114, 120, 126, 132, 138, 144, 150, 156, 162, 168,$ $174, 180, 186, 192, 198$

There are 33 multiples of 6.

• Multiples of 8 are $8, 16, 24, 32, 40, 48, 56, 64, 72, 80, 88, 96, 104,$ $112, 120, 128, 136, 144, 152, 160, 168, 176, 184, 192, 200$

There are 25 multiples of 8.

• But, there are eight common multiples of both 6 and 8$(24, 48, 72, 96, 120, 144, 168, and 192)$  

Hence, the total number of multiples $= 33 + 25 - 8 = 50$

So, probability $= \frac {50}{200} = \frac{1}{4}$or $0.25$