Physics, asked by roopanirvani1394, 8 months ago

a pair of bullocks exerts a force of 140 n on a plough the field being ploughed is 15 M long how much work is done in the ploughing the length of the field​

Answers

Answered by lokeshsharma97150
1

Answer:

w=f×s

Explanation:

w=140n×15m,w=2100j

Answered by Anonymous
3

Force (F) = 1400 N.

Distance (s) = 15m.

\LARGE{\bf{\underline{\underline{TO \ FIND:-}}}}

The work done (w)

\LARGE{\bf{\underline{\underline{SOLUTION:-}}}}

We can use the formula for work done:

\mapsto \sf{\green{W=Fs}}

Where:

F is force.

s is distance.

Substituting the values, we get:

\to \sf W=140 \times 15

\leadsto \sf{\red{2100J}} \bigstar

∴Work done is 2100 J.

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