Question

Find the sum of all three-digit numbers which leave the remainder 3 when divided by .
5.​

Answer 1

Answer:

558

Step-by-step explanation:

558 ÷ 5

quotient =111

remainder = 3

558 is three digit no.

Answer 2

Step-by-step explanation:

smallest 3 digit number which leave the remainder 3 when divided by 5 =103

largest 3 digit number which leave the remainder 3 when divided by 5 =998

3 digit number after 103 which leave the remainder 3 when divided by 5 =108

an ap is formed: 103,108........998

first term=103

common difference=5

let the total no. of three digit numbers which leave the remainder 3 when divided by 5=n

998=103+(n-1)5

180=n

sum of ap=180/2 *(103+998)=90*1101

=99090