Question

a pair of dice is thrown at once find the probability of getting a same number first both doublet second a doublet of prime number 3rd a doublet of odd numbers 4th multiples of 3 as a sum

Answer 1

Here is Your Answer!

Total Outcomes = 36

1) getting same number on both dices or getting a doublet

favourable outcome =6
P(E) = 6/36= 1/6

2) Doublet of a prime number

favourable outcome = 4

P(E) = 4/36 = 1/9

3) doublet of odd numbers

favourable outcome = 3

P(E) = 3/36 = 1/12

4) multiples of 3 as sum
favourable outcome= 11
P(E) = 11/36

Answer 2

Answer:

Oke here is ur answer .. !!