Question

A pair of dice is thrown.If the two numbers appearing on tbem are different,find the probability that the sum of the number is 6

Answer 1

The probability of the sum of the number is 6 is $\frac{5}{36}$.

Step-by-step explanation:

Firstly we will find out the total number of outcomes.

$(1,1),\ (1,2),\ (1,3),\ (1,4),\ (1,5),\ (1,6)$

$(2,1),\ (2,2),\ (2,3),\ (2,4),\ (2,5),\ (2,6)$

$(3,1),\ (3,2),\ (3,3),\ (3,4),\ (3,5),\ (3,6)$

$(4,1),\ (4,2),\ (4,3),\ (4,4),\ (4,5),\ (4,6)$

$(5,1),\ (5,2),\ (5,3),\ (5,4),\ (5,5),\ (5,6)$

$(6,1),\ (6,2),\ (6,3),\ (6,4),\ (6,5),\ (6,6)$

We have to find the probability that the sum of the number is 6.

Total number of outcomes = 36

$(1,5),\ (2,4),\ (3,3),\ (4,2),\ (5,1)$

Total number of possible outcomes = 5

$P(E)=\frac{\textrm{Total number of possible outcomes}}{\textrm{Total number of outcomes}}$

$P(\textrm{ the sum of the number is 6})=\frac{5}{36}$

Hence The probability of the sum of the number is 6 is $\frac{5}{36}$.

Answer 2

Step-by-step explanation:

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