Question

A pair of dice is thrown once. Find the probability of getting :
(1)odd number on each dice
( 2)a total of 8.​

Answer 1

Explanation:

1.

$\frac{1}{2}$

2 same

Answer 2

Answer:

a.$\frac{1}{4}$

b.$\frac{5}{36}$

Explanation:

We are given that a pair of dice is thrown once.

Sample space={(1,1),(1,2)......,(1,6),(2,1),(2,2),....,(2,6),(3,1),...(3,6),(4,1),..(4,6),(5,1),...,(5,6),(6,1),.....,(6,6)}

1.We have to find the probability of getting odd number on each die.

Total number of cases=36

Favorable cases={(1,1),(1,3),(1,5),(3,1),(3,3),(3,5),(5,1)(,5,3),(5,5)}

Number of favorable cases=9

P(E)=$\frac{no\;of\;favorable\;cases}{total\;no\;cases}$

Therefore, probability of getting odd number on each die=$\frac{9}{36}=\frac{1}{4}$

b. Favorable cases={(2,6),(3,5),(4,4),(5,3),(6,2)}

Number of favorable cases=5

The probability of getting a total 8 on both dice=$\frac{5}{36}$