A pair of dice is thrown once. find the probability to getting an odd number on each
Answers
Answered by
9
Answer:
Total outcomes= 36
Favourable outcome=9
P(E) =9/36
=1/4
= 0.25
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Answered by
10
Step-by-step explanation:
a pair of dice is thrown
s={(1,1) ,(1,2),(1,3),(1,4),(1,5),(1,6),
(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)
(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)
(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),
(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),
(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}
n(s) =36
let A be the event of getting odd no. on each dice
A={(1,1),(1,3),(1,5)
(3,1),(3,3),(3,5)
(5,1),(5,3),(5,5)}
n(a) =9
p(a) =n(a) /n(s)
=9/36
p(a) =1/4
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