Math, asked by Anonymous, 1 year ago

A pair of dice is thrown once. find the probability to getting an odd number on each

Answers

Answered by bhaktspattewar88
9

Answer:

Total outcomes= 36

Favourable outcome=9

P(E) =9/36

=1/4

= 0.25

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Answered by nityanivdunge
10

Step-by-step explanation:

a pair of dice is thrown

s={(1,1) ,(1,2),(1,3),(1,4),(1,5),(1,6),

(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)

(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)

(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),

(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),

(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}

n(s) =36

let A be the event of getting odd no. on each dice

A={(1,1),(1,3),(1,5)

(3,1),(3,3),(3,5)

(5,1),(5,3),(5,5)}

n(a) =9

p(a) =n(a) /n(s)

=9/36

p(a) =1/4

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