Question

A pair of dice is thrown once. What is the probability of getting the sum on both the die as 11.

Answer 1

A  die has 6 faces marked as 1,2, 3, 4, 5, 6. When we throw a die , than total number of  outcomes = 6 { 1 , 2 , 3 , 4 , 5 , 6 }
But when we throw  two dice simultaneously , than total number of outcomes =  6² = 6 × 6 = 36
Total possible outcomes on throwing two dice are:
{(1,1),(1,2),(1,3),(1,4),(1,5),(1,6), (2,1),(2,2),(2,3),(2,4),(2,5),(2,6), (3,1),(3,2),(3,3),(3,4),(3,5),(3,6), (4,1),(4,2),(4,3),(4,4),(4,5),(4,6), (5,1),(5,2),(5,3),(5,4),(5,5),(5,6), (6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}
Number of all possible outcomes=36
SOLUTION:
Total number of outcomes= 36

Favourable outcomes are : (5,6),(6,5)
Number of outcomes favourable = 2

Probability = Number of favourable outcomes / Total number of outcomes.

Required probability = P(getting  the sum on both the die as 11) = 2 /36 = 1/18

Hence, the probability of  getting the sum on both the die  as 11 = 1/ 18.

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