Question

A pair of dice is tossed twice. Find the probability that both rolls give a sum of 8.
a-5/36
b- 25/36
c- 25/1296
d-5/1296
e- None of these​

Answer 1

Answer:

p(AandB)=p(a)×p(b)

A=sum of two dice will be 8

p(a)=5/36

b=sum of two dice will be 8

p(b)=5/36

p(Aand B)=5/36×5/36

=answer is 25/1296

Answer 2

Answer:

so, the probability that both rolls give a sum of 8= 51296

Step-by-step explanation:

total number of outcomes when two dies are thrown = n(S) = 6^4=1296

favourable outcomes are (2, 6),( 3,5)(4, 4), (5, 3) (6,2)

number of favourable outcomes=n(E) = 5

probability of getting sum 8 = number of favourable outcomes/total outcomes = n(E) /n(S) = 5/36

so, the probability that both rolls give a sum of 8= 5/1296

option d. . 5/1296