A pair of die is thrown once(i) write sample space for the experiment2)find the probability of getting an odd number on each die.
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Answer:
A pair of dice is thrown once = 6×6 = 36
i) sample space = 36
ii) Favorable cases={(1,1),(1,3),(1,5),(3,1),(3,3),(3,5),(5,1)(,5,3),(5,5)}
Number of favorable outcome = 9
P(E) = no. of favorable outcome / sample space
Therefore, probability of getting odd number on each die= 9/36 = 1/4 ...
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Step-by-step explanation:
bhaiya thank you very much
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