a pair of four sided dice is rolled and the sum is determined. what is the probability that a sum of 3 is rolled before a sum of 5 is rolled in a sequence of rolls of the dice?
Answers
Answer:
1/3
Step-by-step explanation:
There are 2 ways of making 3(12,21), 4 ways of making 5(14,41,23,32) and 10 ways of making anything else.
Represent these possibilities by 1,2,5 - we wish to determine the probability of 1 occurring before 2.
We can ignore all initial throws of 5, and as each throw is independent, the problem reduces to which occurs first of 1 and 2.
As 2 is twice as likely to happen as 1, the answer is 13.
Answer:
The probability that a sum of 3 is rolled before a sum of 5 is rolled in a sequence of rolls of the dice is 1/9.
Question : A pair of four sided dice is rolled and the sum is determined. what is the probability that a sum of 3 is rolled before a sum of 5 is rolled in a sequence of rolls of the dice?
Step-by-step explanation:
From the above question,
They have given :
A pair of four sided dice is rolled and the sum is determined.
There are 6 possible outcomes when a pair of four sided dice is rolled:
1+2, 1+3, 1+4, 2+1, 2+2, 2+3, 2+4, 3+1, 3+2, 3+3, 3+4, 4+1, 4+2, 4+3, 4+4.
The probability of rolling a sum of 3 is 1/9 and the probability of rolling a sum of 5 is 1/9.
Therefore, the probability that a sum of 3 is rolled before a sum of 5 is rolled in a sequence of rolls of the dice is 1/9.
Calculate the total number of outcomes when a pair of four sided dice is rolled.
Calculate the probability of rolling a sum of 3.
Calculate the probability of rolling a sum of 5.
Calculate the probability that a sum of 3 is rolled before a sum of 5 is rolled in a sequence of rolls of the dice.
The probability that a sum of 3 is rolled before a sum of 5 is rolled in a sequence of rolls of the dice is 1/9.
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