the maximum speed of the to Tsunami is 240 metre per second calculate the kinetic energy present in 1 kilogram water of the tide
Answers
Answered by
12
Answer:
28800J
Explanation:
kinetic energy =m×a×s(displacement) work
m×a=force,force×displacement =work
work is related to energy
third equation for motion =v²-u²=2as
s=v²-u²/2a
here initial velocity =u=0m/s
hence s=v²/2a
m×a×v²/2a
m×1×v²/2
mv²/2 = kinetic energy
1×(240)²/2=28800 J
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Answered by
3
Answer: 28800
Explanation:
mass of the body ( m ) = 1
velocity ( v ) = 240m/s
kinetic energy ( KE ) = ?
we have,
KE = 1/2 mv^2
= 1/2 * 1 * 240^2
= 28800 J/kg
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