Physics, asked by suraj5912, 10 months ago

the maximum speed of the to Tsunami is 240 metre per second calculate the kinetic energy present in 1 kilogram water of the tide​

Answers

Answered by priyankapriyanka1980
12

Answer:

28800J

Explanation:

kinetic energy =m×a×s(displacement) work

m×a=force,force×displacement =work

work is related to energy

third equation for motion =v²-u²=2as

s=v²-u²/2a

here initial velocity =u=0m/s

hence s=v²/2a

m×a×v²/2a

m×1×v²/2

mv²/2 = kinetic energy

1×(240)²/2=28800 J

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Answered by aasth71
3

Answer: 28800

Explanation:  
mass of the body ( m ) = 1
velocity ( v ) = 240m/s
kinetic energy ( KE ) = ?
we have,
KE = 1/2 mv^2
     = 1/2 * 1 * 240^2
     = 28800 J/kg

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