a pair of integers whose product is -36and difference is 15
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let one integer be X, the other will be X+15
given that
X(X+15)= -36
X² +15X +36=0
= X²+12X+3X+36=0
= (X+3)(X+12)=0
X = -3,-12
when X is -3
integers are -3 and 12
when X is -12
integers are -12 and 3
given that
X(X+15)= -36
X² +15X +36=0
= X²+12X+3X+36=0
= (X+3)(X+12)=0
X = -3,-12
when X is -3
integers are -3 and 12
when X is -12
integers are -12 and 3
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