Question

Find the value of p, for which one root of the quadratic equation

px2

14x + 8 = 0 is 6 times the other.

Answer 1

let the roots be a and 6a .

sum of roots =-b/a

so, 14/p = 7a 

14/7p = a 

2/p = a

product of roots= 6[tex] a^{2} [/tex] = 8/p

= 4/p = 3$a^{2}$

= 4/p = 3$(2/p) ^{2}$

= 3/p=1

p=3

Answer 2

p=3
sum of zeroes=-14/p
product of zeroes = 8/p
where u will get alpha = 2/p
substitute in product of zeroes