Question

A palm fruit dropped to the ground front the top of a tree 45 m tall. How long does it take to reach the ground?
(A) 9 seconds (B) 4.5 seconds
(C) 3 seconds (D) 7.5 seconds

Explain with solving​

Answer 1

Explanation:

s=(1/2)gt^2

45=0.5*10t^2

9=t square

t=3

Answer 2

Answer:

time=3 sec

Explanation:

Acc to motion in straight line formulae

h=ut+1/2gt^2

*Here they used the term DROPPED so we must take the initial velocity u=0*

So h=0+1/2gt^2

And here h=45m

They asked t=?

45=1/2×9.8×t^2 : here g=9.8

90/10=t^2 : 9.8 is approx to 10

So t=3 sec